Use B and C for this item. An Ansible automation uses playbooks and tasks to define work such as configuring a VLAN. The playbook organizes the automation, while tasks call modules or commands to produce the desired configuration on managed devices. In Cisco CCNA 200-301 v1.1, Automation and Programmability questions frequently test the practical boundary between similar features: what the feature does, where it is configured, and what problem it is meant to solve. Cookbooks and recipes are Chef terms, and a model is not the Ansible component required here. A clean way to validate the answer is to map the wording of the scenario to the actual device function. If the feature supplies addressing, forwarding, authentication, trunking, route selection, or controller communication, the answer must match that function exactly rather than a nearby protocol name.

Only controller-based networks decouple the control plane and the data plane. Automation questions require separating controller roles, API direction, data formats, HTTP behavior, and configuration-management tooling. Cisco CCNA 200-301 v1.1 includes this topic under Automation and Programmability, so the answer must be validated against normal Cisco device behavior and the operational wording of the scenario. The key is not simply recognizing a familiar acronym; it is identifying what the feature does, where it is configured, and what result it produces. The incorrect options mix northbound and southbound communication, confuse data serialization with transport, or describe traditional device-by-device management. In a real network, selecting the wrong option would either leave the feature nonfunctional, create a forwarding or security gap, or send troubleshooting in the wrong direction. The selected answer is the only one that matches the stated requirement and the way Cisco switching, routing, services, security, wireless, or automation functions are expected to operate. This is why the verified answer remains the best technical choice for the question.

route learned through EIGRP. EIGRP route selection uses feasible distance, reported distance, successor and feasible-successor logic, with bandwidth and delay forming the default composite metric. Cisco CCNA 200-301 v1.1 includes this topic under IP Connectivity, so the answer must be validated against normal Cisco device behavior and the operational wording of the scenario. The key is not simply recognizing a familiar acronym; it is identifying what the feature does, where it is configured, and what result it produces. Options that describe hop count, OSPF cost, or unrelated K-value behavior do not describe the default EIGRP decision process. In a real network, selecting the wrong option would either leave the feature nonfunctional, create a forwarding or security gap, or send troubleshooting in the wrong direction. The selected answer is the only one that matches the stated requirement and the way Cisco switching, routing, services, security, wireless, or automation functions are expected to operate. This is why the verified answer remains the best technical choice for the question.

This item belongs to Cisco CCNA 200-301 v1.1 Network Fundamentals, where the exam measures whether the candidate can match a technology, field, protocol, or network behavior to its correct operational role. The important step is to classify each left-side item by what it actually does, not by a similar-sounding term. For example, management protocols, address types, QoS mechanisms, wireless settings, and topology terms all have strict meanings in Cisco documentation and IOS behavior. A wrong match usually places a function at the wrong layer or assigns a feature to the wrong control point. The shown mapping keeps those boundaries intact: the component that performs the function is paired with the matching description, while unrelated distractors are left unused or mapped elsewhere. In real troubleshooting, this same skill prevents engineers from applying a security, routing, switching, or automation feature in the wrong part of the design.

The correct response is D. Physical access control regulates access to networking equipment, rooms, racks, and facilities. Examples include locks, badges, guards, cameras, mantraps, and visitor controls around wiring closets and data centers. For Cisco CCNA 200-301 v1.1, the important point is the mechanism, not a generic description of the technology. Access to file systems and specific networks is logical access control, not physical access control. When this appears in a network, the symptom normally confirms the answer: the route installed, the state selected, the packet forwarded, the wireless client behaviour, or the management workflow will follow this rule. That is why this answer is the best fit for the scenario and not just a plausible networking term.

Answer as below configuration:

On R2:

Enable

Conf t

Ip route 192.168.1.0 255.255.255.0 10.10.31.1

On R1:

Enable

Conf t

Ip route 0.0.0.0 0.0.0.0 10.10.13.3

On R2

Ip route 172.20.20.128 255.255.255.128 e0/2

Ip route 172.20.20.128 255.255.255.128 e0/1

On R1

Ip route 192.168.0.0 255.255.255.0 e0/1

Ip route 192.168.0.0 255.255.255.0 10.10.12.2 3

Save all configurations after every router from anyone of these command

Do wr

Or

Copy run start

Answer as below configuration:

on R1

conf terminal

interface Loopback0

ip address 10.10.1.1 255.255.255.255

!

interface Loopback1

ip address 192.168.1.1 255.255.255.0

!

interface Ethernet0/0

no shut

ip address 10.10.12.1 255.255.255.0

ip ospf 1 area 0

duplex auto

!

interface Ethernet0/1

no shut

ip address 10.10.13.1 255.255.255.0

ip ospf 1 area 0

duplex auto

!

router ospf 1

router-id 10.10.12.1

network 10.10.1.1 0.0.0.0 area 0

network 192.168.1.0 0.0.0.255 area 0

!

copy run star

---------------------------------------

On R2

conf terminal

interface Loopback0

ip address 10.10.2.2 255.255.255.255

!

interface Loopback1

ip address 192.168.2.2 255.255.255.0

!

interface Ethernet0/0

no shut

ip address 10.10.12.2 255.255.255.0

ip ospf priority 255

ip ospf 1 area 0

duplex auto

!

interface Ethernet0/2

no shut

ip address 10.10.23.2 255.255.255.0

ip ospf priority 255

ip ospf 1 area 0

duplex auto

!

router ospf 1

network 10.10.2.2 0.0.0.0 area 0

network 192.168.2.0 0.0.0.255 area 0

!

copy runs start

-----------------------

On R3

conf ter

interface Loopback0

ip address 10.10.3.3 255.255.255.255

!

interface Loopback1

ip address 192.168.3.3 255.255.255.0

!

interface Ethernet0/1

no shut

ip address 10.10.13.3 255.255.255.0

ip ospf 1 area 0

duplex auto

!

interface Ethernet0/2

no shut

ip address 10.10.23.3 255.255.255.0

ip ospf 1 area 0

duplex auto

!

router ospf 1

network 10.10.3.3 0.0.0.0 area 0

network 192.168.3.0 0.0.0.255 area 0

!

copy run start

!

Answer as below configuration:

On SW1:

conf terminal

vlan 15

exit

interface range eth0/0 - 1

channel-group 1 mode active

exit

interface port-channel 1

switchport trunk encapsulation dot1q

switchport mode trunk

switchport trunk native vlan 15

end

copy run start

on SW2:

conf terminal

vlan 15

exit

interface range eth0/0 - 1

channel-group 1 mode active

exit

interface port-channel 1

switchport trunk encapsulation dot1q

switchport mode trunk

switchport trunk native vlan 15

end

copy run start

To configure static routing on R1 to ensure that it prefers the path through R2 to reach only PC1 on R4’s LAN, you need to create a static route for the host 10.0.0.100/8 with a next-hop address of 20.0.0.2, which is the IP address of R2’s interface connected to R1. You also need to assign a lower administrative distance (AD) to this route than the default AD of 1 for static routes, so that it has a higher preference over other possible routes. For example, you can use an AD of 10 for this route. To create this static route, you need to enter the following commands on R1’s console:

R1#configure terminal R1(config)#ip route 10.0.0.100 255.0.0.0 20.0.0.2 10 R1(config)#end

To configure static routing on R1 that ensures that traffic sourced from R1 will take an alternate path through R3 to PC1 in the event of an outage along the primary path, you need to create another static route for the host 10.0.0.100/8 with a next-hop address of 40.0.0.2, which is the IP address of R3’s interface connected to R1. You also need to assign a higher AD to this route than the AD of the primary route, so that it has a lower preference and acts as a backup route. For example, you can use an AD of 20 for this route. This type of static route is also known as a floating static route. To create this static route, you need to enter the following commands on R1’s console:

R1#configure terminal R1(config)#ip route 10.0.0.100 255.0.0.0 40.0.0.2 20 R1(config)#end

To configure default routes on R1 and R3 to the Internet using the least number of hops, you need to create a static route for the network 0.0.0.0/0 with a next-hop address of the ISP’s interface connected to each router respectively. A default route is a special type of static route that matches any destination address and is used when no other specific route is available. The ISP’s interface connected to R1 has an IP address of 10.0.0.4, and the ISP’s interface connected to R3 has an IP address of 50.0.0.4. To create these default routes, you need to enter the following commands on each router’s console:

On R1: R1#configure terminal R1(config)#ip route 0.0.0.0 0.0.0.0 10.0.0.4 R1(config)#end

On R3: R3#configure terminal R3(config)#ip route 0.0.0.0 0.0.0.0 50.0.0.4 R3(config)#end

Answer as below configuration:

on R1

config terminal

ipv6 unicast-routing

inter eth0/1

ip addre 192.168.1.1 255.255.255.240

ipv6 addre 2001:db8:aaaa::1/64

not shut

end

copy running start

on R2

config terminal

ipv6 unicast-routing

inter eth0/1

ip address 192.168.1.14 255.255.255.240

ipv6 address 2001:db8:aaaa::2/64

not shut

end

copy running start

---------------------

for test from R1

ping ipv6 2001:db8:aaaa::1

for test from R2

ping ipv6 2001:db8:aaaa::2

To configure an LACP EtherChannel and number it as 44, configure it between switches SW1 and SW2 using interfaces Ethernet0/0 and Ethernet0/1 on both sides, configure the EtherChannel as a trunk link, configure the trunk link with 802.1q tags, and configure VLAN ‘MONITORING’ as the untagged VLAN of the EtherChannel, you need to follow these steps:

On both SW1 and SW2, enter the global configuration mode by using the configure terminal command.

On both SW1 and SW2, select the two interfaces that will form the EtherChannel by using the interface range ethernet 0/0 - 1 command. This will enter the interface range configuration mode.

On both SW1 and SW2, set the protocol to LACP by using the channel-protocol lacp command.

On both SW1 and SW2, assign the interfaces to an EtherChannel group number 44 by using the channel-group 44 mode active command. This will create a logical interface named Port-channel44 and set the LACP mode to active on both ends. The LACP mode must match on both ends for the EtherChannel to form.

On both SW1 and SW2, exit the interface range configuration mode by using the exit command.

On both SW1 and SW2, enter the Port-channel interface configuration mode by using the interface port-channel 44 command.

On both SW1 and SW2, configure the Port-channel interface as a trunk link by using the switchport mode trunk command.

On both SW1 and SW2, configure the Port-channel interface to use 802.1q tags for VLAN identification by using the switchport trunk encapsulation dot1q command.

On both SW1 and SW2, configure VLAN ‘MONITORING’ as the untagged VLAN of the Port-channel interface by using the switchport trunk native vlan MONITORING command.

On both SW1 and SW2, exit the Port-channel interface configuration mode by using the exit command.

On both SW1 and SW2, save the configuration to NVRAM by using the copy running-config startup-config command.

Answer as below configuration:

1.- on R3

config terminal

ip route 192.168.1.1 255.255.255.255 209.165.200.229

end

copy running start

2.- on R2

config terminal

ip route 0.0.0.0 0.0.0.0 209.165.202.130

end

copy running start

3.- on R2

config terminal

ipv6 route ::/0 2001:db8:abcd::2

end

copy running start

To subnet 172.25.0.0/16 to meet the subnet requirements and maximize the number of hosts, you need to determine how many bits you need to borrow from the host portion of the address to create enough subnets for 32 sites. Since 32 is 2^5, you need to borrow 5 bits, which means your new subnet mask will be /21 or 255.255.248.0. To find the second subnet, you need to add the value of the fifth bit (32) to the third octet of the network address (0), which gives you 172.25.32.0/21 as the second subnet. The first usable IP address in this subnet is 172.25.32.1, and the last usable IP address is 172.25.39.254.

To assign the first usable IP address to e0/0 on Sw101, you need to enter the following commands on the device console:

Sw101#configure terminal Sw101(config)#interface e0/0 Sw101(config-if)#ip address 172.25.32.1 255.255.248.0 Sw101(config-if)#no shutdown Sw101(config-if)#end

To assign the last usable IP address to e0/0 on Sw102, you need to enter the following commands on the device console:

Sw102#configure terminal Sw102(config)#interface e0/0 Sw102(config-if)#ip address 172.25.39.254 255.255.248.0 Sw102(config-if)#no shutdown Sw102(config-if)#end

To subnet an IPv6 GUA to meet the subnet requirements and maximize the number of hosts, you need to determine how many bits you need to borrow from the interface identifier portion of the address to create enough subnets for 32 sites. Since 32 is 2^5, you need to borrow 5 bits, which means your new prefix length will be /69 or ffff:ffff:ffff:fff8::/69 (assuming that your IPv6 GUA has a /64 prefix by default). To find the second subnet, you need to add the value of the fifth bit (32) to the fourth hextet of the network address (0000), which gives you xxxx:xxxx:xxxx:0020::/69 as the second subnet (where xxxx:xxxx:xxxx is your IPv6 GUA prefix). The first and last IPv6 addresses in this subnet are xxxx:xxxx:xxxx:0020::1 and xxxx:xxxx:xxxx:0027:ffff:ffff:ffff:fffe respectively.

To assign an IPv6 GUA using a unique 64-bit interface identifier on e0/0 on Sw101, you need to enter the following commands on the device console (assuming that your IPv6 GUA prefix is 2001:db8::/64):

Sw101#configure terminal Sw101(config)#interface e0/0 Sw101(config-if)#ipv6 address 2001:db8::20::1/69 Sw101(config-if)#no shutdown Sw101(config-if)#end

To assign an IPv6 GUA using a unique 64-bit interface identifier on e0/0 on Sw102, you need to enter the following commands on the device console (assuming that your IPv6 GUA prefix is 2001:db8::/64):

Sw102#configure terminal Sw102(config)#interface e0/0 Sw102(config-if)#ipv6 address 2001:db8::27::fffe/69 Sw102(config-if)#no shutdown Sw102(config-if)#end

Answer as below configuration:

on sw1

enable

conf t

vlan 100

name Compute

vlan 200

name Telephony

int e0/1

switchport voice vlan 200

switchport access vlan 100

int e0/0

switchport mode access

do wr

on sw2

Vlan 99

Name Available

Int e0/1

Switchport access vlan 99

do wr

Answer as below configuration:

Sw1

enbale

config t

Vlan 210

Name FINANCE

Inter e0/1

Switchport access vlan 210

do wr

Sw2

Enable

config t

Vlan 110

Name MARKITING

Int e0/1

Switchport acees vlan 110

do wr

Sw3

Enable

config t

Vlan 110

Name MARKITING

Vlan 210

Name FINANCE

Int e0/0

Switchport access vlan 110

Int e0/1

Switchport access vlan 210

Sw1

Int e0/1

Switchport allowed vlan 210

Sw2

Int e0/2

Switchport trunk allowed vlan 210

Sw3

Int e0/3

Switchport trunk allowed vlan 210

Switchport trunk allowed vlan 210,110

Answer as below configuration:

conf t

R1(config)#ntp master 1

R2(config)#ntp server 10.1.2.1

Exit

Router#clock set 00:00:00 jan 1 2019

ip dhcp pool TEST

network 10.1.3.0 255.255.255.0

ip dhcp exluded-address 10.1.3.1 10.1.3.10

R3(config)#int e0/3

R3(config)#int e0/2

ip address dhcp

no shut

crypto key generate RSA

1024

Copy run start

Cisco CCNA 200-301 v1.1 Network Fundamentals questions of this type test whether each item is matched to the technology that actually performs that role. The reliable method is to classify each term by operating layer, packet behavior, management function, or security purpose before matching it. Several terms in these items are legitimate Cisco networking concepts, but they become wrong when assigned to the wrong protocol or plane. The mapping retained in the document follows that separation: transport behavior is matched to TCP or UDP, wireless or security terms are matched to their mechanisms, and automation items are matched to the correct API or management model. This matters operationally because troubleshooting fails quickly when a forwarding-plane function is treated as a management-plane feature or when a security control is applied to the wrong threat. The shown mapping is therefore retained as the verified response.

Both use the same data-link header and trailer formats. The answer follows directly from normal Cisco device behavior and the wording of the scenario. Cisco CCNA 200-301 v1.1 includes this under Network Fundamentals, where the exam expects engineers to recognize the device behavior that actually produces the required outcome. The question is best solved by reading the operational clue rather than choosing a familiar acronym. The other choices are either adjacent technologies, wrong-layer functions, or settings that would not produce the stated result. In a production network, the wrong choice would normally create an outage, leave a management or security gap, or send troubleshooting toward the wrong subsystem. The selected answer is the one that matches the control-plane, data-plane, wireless, security, services, or automation mechanism described in the question. That is why it remains the verified answer for this item.

between zones 3 and 6. Wireless operation depends on WLAN identity, AP mode, RF management, client authentication, and controller-based policy enforcement. Cisco CCNA 200-301 v1.1 includes this under Network Access, where the exam expects engineers to recognize the device behavior that actually produces the required outcome. The question is best solved by reading the operational clue rather than choosing a familiar acronym. The distractors confuse WLAN names, authentication, encryption, RF optimization, and controller management functions. In a production network, the wrong choice would normally create an outage, leave a management or security gap, or send troubleshooting toward the wrong subsystem. The selected answer is the one that matches the control-plane, data-plane, wireless, security, services, or automation mechanism described in the question. That is why it remains the verified answer for this item.

ipv6 address 2001:DB8:0:1:C601:42FF:FE0F:7/64. Cisco routers select forwarding paths by longest-prefix match first, then administrative distance and metric when comparable routes compete. Cisco CCNA 200-301 v1.1 includes this under IP Connectivity, where the exam expects engineers to recognize the device behavior that actually produces the required outcome. The question is best solved by reading the operational clue rather than choosing a familiar acronym. The wrong choices either do not match the destination, use the wrong next hop, or fail to provide the intended primary/backup behavior. In a production network, the wrong choice would normally create an outage, leave a management or security gap, or send troubleshooting toward the wrong subsystem. The selected answer is the one that matches the control-plane, data-plane, wireless, security, services, or automation mechanism described in the question. That is why it remains the verified answer for this item.